Kevin Nash
Last Activity: 10 Years ago
Sol. E = 100 V, R’ = 100 kΩ = 100000 Ω
R = 1 – 100
When no other resister is added or R = 0.
i = E/R’ = 100/100000 = 0.00 1Amp
when R = 1
i = 100/100000 + 1 = 100/100001 = 0.0009A
when R = 100
i = 100/100000 + 1 = 100/100100 = 0.0009999 A.
Upto R = 100 the current does not upto 2 significant digits. Thus it proved.