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Grade: 10
        A 20 μF capacitor is joined to a battery of emf 6.0 V through a resistance of 100 Ω. Find the charge on the capacitor 2.0 ms after the connections are made. 
5 years ago

Answers : (1)

Jitender Pal
askIITians Faculty
365 Points
							Sol. C = 20 * 10^–6 F, E = 6 V, R = 100 Ω
t = 2 * 10^–3 sec
q = EC (1 – e^–t/RC)
= 6 * 20 * 10^-6 (1 – e^-2*10^-3/100*20*10^-6)
= 12 x 10^–5 (1 – e^–1) = 7.12 * 0.63 * 10^–5 = 7.56 * 10^–5
= 75.6 * 10^–6 = 76 μc.

						
5 years ago
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