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A 20 cm long conducting rod is set into pure translation with a uniform velocity of 10 cm/s perpendicular to its length. A uniform magnetic field of magnitude 0.10 T exists in a direction perpendicular to the plane of motion. (a) Find the average magnetic force on the free electrons of the rod. (b) For what electric field inside the rod, the electric force on a free electron will balance the magnetic force? How is this electric field created? (c) Find the motional emf between the ends of the rod.

A 20 cm long conducting rod is set into pure translation with a uniform velocity of 10 cm/s perpendicular to its length. A uniform magnetic field of magnitude 0.10 T exists in a direction perpendicular to the plane of motion. (a) Find the average magnetic force on the free electrons of the rod. (b) For what electric field inside the rod, the electric force on a free electron will balance the magnetic force? How is this electric field created? (c) Find the motional emf between the ends of the rod.

Grade:11

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
8 years ago
Sol. l = 20 cm = 0.2 m v = 10 cm/s = 0.1 m/s B = 0.10 T a) F = q v B = 1.6 × 10^–19 × 1 × 10^–1 × 1 × 10^–1 = 1.6 × 10^–21 N b) qE = qvB ⇒ E = 1 × 10^–1 × 1 × 10^–1 = 1 × 10^–2 V/m This is created due to the induced emf. c) Motional emf = Bvℓ = 0.1 × 0.1 × 0.2 = 2 × 10^–3 V

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