pratham ashish
hi,
peak value of emf depends on (when current remain constant) the impedence of the circuit.
In the case where there is just an inductor the impedence will be equal to X(l) (inductive
reactance)if there is no resistance in the circuit. if we also consider the circuit to have
some resistance then the impedence will be given by (r^2 + x(l)^2)^1/2.
where r is the resistance.
if only reactance is considered then the emf can be greater but if resistance is also taken in
to account and it is same for both the circuits.. along with the value of L. i.e. both circuits
have equal L and R then the LCR circuit will always have larger emf because in this case the
impedence would be given by ( R^2 + (X(l) - X(c))^2 ) ^1/2.. where X(c) is the capcitive
reactance.
