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Electromagnetic Induction

A uniform magnetic field of induction B is changing in magnitude at a constant rate dB/dt. copper wire of mass M is to be drawn into wire of rdius r and formed into a circular loop of radius R. If P(rho) is the specific resistance and delta( ) is the density of wire, then what is the induced current in the loop? Assume B is perpendicular to the loop..

Profile image of SAURABH ATIREK
15 Years agoGrade
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1 Answer

Profile image of Chetan Mandayam Nayakar
15 Years ago

Dear Saurabh, 

Resistance s=ρl/A,l=2πr, A=πr2, s=2ρR/r2, V= d/dt(πR2B)=πR2dB/dt, current I=V/s =(πRr2/2ρ)(dB/dt)

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