In a circuit containing a capacitor and an AC source, the current is zero at the instant the source voltage is maximum. Is it consistent with ohm’s law?

Question

In a circuit containing a capacitor and an AC source, the current is zero at the instant the source voltage is maximum. Is it consistent with ohm&rsquo;s law?

kedar joshi · Answer

when only a capacitor is atached to the ac source the current and emf have a phase difference of (pi/2) i.e.90degree therefore i=imax(sin wt) while emf =emax(sin wt+(pi/2)) while this circuit not having any resistance not follow ohm's law

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

In a circuit containing a capacitor and an AC source, the current is zero at the instant the source voltage is maximum. Is it consistent with ohm’s law?

In a circuit containing a capacitor and an AC source, the current is zero at the instant the source voltage is maximum. Is it consistent with ohm’s law?

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Electromagnetic Induction

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship