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Electromagnetic Induction

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Profile image of sunny chawla
15 Years agoGrade
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1 Answer

Profile image of Gokul  Joshi AskiitiansExpert-IITK
ApprovedApproved Tutor Answer15 Years ago

Dear Sunny,

(i) Initial flux = nBiA = 50*7*10-2*200*10-4 Wb = 7*10-2 Wb
(ii) Final flux = nBfA = 50*2*10-2*200*10-4 Wb = 2*10-2 Wb
(iii) EMF = ΔΦ/Δt = 5*10-2/0.04 V = 1.25 V


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Gokul  Joshi