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you had answered my question regarding EMI

I understood the explanation but I have a few doubts:

1.In the step XL=2πfL why have you used 5/100?

2.You have taken a parallel combination of inductor and resistor..but I have read that inductor allows dc current to flow through it easily,so there will be no current in resistor,please explain

3The fact that the key is just pressed,Does it have any effect on the outcome?

Please explain....I need your help!

Siddharth Singhania , 15 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

It's great that you're diving deeper into the topic of Electromagnetic Induction (EMI) and have some specific questions. Let's tackle each of your doubts one by one to clarify your understanding.

Understanding the Formula: XL = 2πfL

In the formula XL = 2πfL, the term "f" represents the frequency of the alternating current (AC) in hertz (Hz), and "L" is the inductance in henries (H). The expression 5/100 likely refers to a specific frequency value used in a particular example. If we assume that the frequency is 5 Hz, then the calculation would be:

  • f = 5 Hz
  • L = 0.1 H (for example)
  • XL = 2π(5)(0.1) = 3.14 Ω

So, the 5/100 might have been a way to express a frequency value in a specific context. If you have a different frequency in mind, just plug that value into the formula to find the inductive reactance.

Inductor Behavior in DC Circuits

You've mentioned that an inductor allows DC current to flow through it easily, which is true but needs some clarification. When a DC voltage is applied to an inductor, it initially opposes the change in current due to its inductance. However, once the current reaches a steady state, the inductor behaves like a short circuit, allowing DC to flow through it with minimal resistance.

In a parallel combination of an inductor and a resistor, when the circuit is first energized, the inductor will initially resist the change in current. Over time, as the current stabilizes, the inductor will allow the DC current to flow, and the resistor will also have current flowing through it. The current through the resistor will depend on the resistance value and the voltage applied. So, while the inductor does allow DC to flow, it does not mean that the resistor will have zero current; it will have current based on the overall circuit conditions.

Impact of Pressing the Key

When you press a key in an electrical circuit, you're essentially closing the circuit, allowing current to flow. The act of pressing the key has a significant effect on the outcome of the circuit's behavior. Initially, when the key is pressed, the circuit experiences a sudden change in current, which can induce a voltage across the inductor due to its property of opposing changes in current.

This transient response can lead to a temporary spike in voltage across the inductor, which can affect other components in the circuit. After the initial transient period, the circuit will settle into a steady state where the current stabilizes. The duration and characteristics of this transient response depend on the values of the inductor and resistor in the circuit.

Summary of Key Points

  • The formula XL = 2πfL uses frequency and inductance to calculate inductive reactance.
  • Inductors initially resist changes in current but eventually allow DC to flow freely.
  • Pressing the key closes the circuit, causing transient responses that affect current and voltage in the circuit.

Feel free to ask more questions if you need further clarification on any of these points! Understanding these concepts will greatly enhance your grasp of electromagnetic induction and circuit behavior.

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