Flag Electromagnetic Induction> In 110 V compound generator the resistanc...
question mark

In 110 V compound generator the resistance of armature s h u n t and series windings are 0.06 ohms, 25 ohms and 0.04 ohms respectively the the load consists of 200 lamp each rated at 55 w, 110 volts find the total electromotive force and armature current and the machine is connected a) long s h u n t ; b) short shunt. Ignore armature reaction and brush contact drop.

chandrashekhar , 9 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To solve this problem, we need to analyze the circuit of a compound generator under two configurations: long shunt and short shunt. We will calculate the total electromotive force (EMF) and the armature current for both setups. Let's break this down step by step.

Understanding the Load

The load consists of 200 lamps, each rated at 55 watts and 110 volts. First, we need to determine the total load current:

  • Power of one lamp = 55 W
  • Total power for 200 lamps = 200 lamps × 55 W/lamp = 11,000 W
  • Voltage = 110 V
  • Total current (I) = Total power / Voltage = 11,000 W / 110 V = 100 A

Long Shunt Configuration

In a long shunt configuration, the shunt winding is connected across the load, while the series winding is connected in series with the load. The total resistance in the circuit can be calculated as follows:

  • Resistance of armature (Ra) = 0.06 ohms
  • Resistance of shunt winding (Rsh) = 25 ohms
  • Resistance of series winding (Rs) = 0.04 ohms

The total resistance in the circuit for the long shunt is:

R_total = Ra + Rs = 0.06 ohms + 0.04 ohms = 0.10 ohms

Calculating the Total EMF

The total EMF (E) can be calculated using the formula:

E = I × R_total + V_load

Substituting the values:

E = 100 A × 0.10 ohms + 110 V = 10 V + 110 V = 120 V

Finding Armature Current

In the long shunt configuration, the armature current (Ia) is equal to the load current (I) since the series winding carries the same current as the load:

Ia = I = 100 A

Short Shunt Configuration

In a short shunt configuration, only the shunt winding is connected across the load, and the series winding is connected in series with the armature. The total resistance in this case is:

R_total = Ra + Rsh = 0.06 ohms + 25 ohms = 25.06 ohms

Calculating the Total EMF for Short Shunt

Using the same formula for EMF:

E = Ia × R_total + V_load

However, we need to find the armature current (Ia) first. The current through the shunt winding (Ish) can be calculated as:

Ish = V_load / Rsh = 110 V / 25 ohms = 4.4 A

Now, the armature current is the sum of the load current and the shunt current:

Ia = I + Ish = 100 A + 4.4 A = 104.4 A

Finding Total EMF for Short Shunt

Now we can substitute this value back into the EMF equation:

E = 104.4 A × 25.06 ohms + 110 V

E = 2,617.784 V + 110 V = 2,727.784 V

Summary of Results

To summarize the findings:

  • Long Shunt: Total EMF = 120 V, Armature Current = 100 A
  • Short Shunt: Total EMF = 2,727.784 V, Armature Current = 104.4 A

This analysis illustrates how the configuration of the generator affects both the total EMF and the armature current. In practical applications, understanding these differences is crucial for efficient generator operation and load management.

ApprovedApproved
Last Activity: 9 Months ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments