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we know that
the relation between terminal voltage (V) and emf (E) of a battery is given as
V = E - Ir
here,
E = 12 volts
I = 90 amps
r = 0.05 ohms
so,
V = 12 - 90x0.05
thus, terminal voltage
V = 7.5 volts
now,
the maximum current will be calculated for a short circuit when voltage is zero
so, if V = 0
E = Ir
or
Imax = E/r
r = 500 ohms
Imax = 12/500
thus, maximum current
Imax = 0.024 amps
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