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What will happen when 40 W ,220V lamp and 100W,220V lamp are connected in series across 440V supply? Will both lamps fuse or only one lamp fuse or no one fuses? And if only one lamp fuses, which one and why? I did it using P=I*V since in series I=constant so P1/V1=P2/V2 where V2=440-V1 after solving I get V1=88 and V2=352 so bulb 2 should fuse but instead the answer is that bulb 1 should fuse. Can you explain me my mistake ??

What will happen when 40 W ,220V lamp and 100W,220V lamp are connected in series across 440V supply?Will both lamps fuse or only one lamp fuse or no one fuses? And if only one lamp fuses, which one and why?
I did it using P=I*V since in series I=constant so P1/V1=P2/V2 where V2=440-V1
after solving I get V1=88 and V2=352 so bulb 2 should fuse but instead the answer is that bulb 1 should fuse. Can you explain me my mistake ??

Grade:12

1 Answers

Aayush Seth
19 Points
7 years ago
First of all check your calculations v1 is 125.7 and v2 is 314.3. Your answer is correct as the maximum current that bulb 1 can accept is 0.2A while bulb 2 can accept 0.44A. The current in the circuit can not exceed 0.27A so bulb 2 will have to get fused. Better approach in this type of questions is to calculate the individual resistance first by p=v2/r then calculate the current in the circuit.

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