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Two stones are thrown with the same speed but making different angles with the horizontal. Their ranges are equal. If the angle of projection of one is ?/3 and its maximum height is y1 then the maximum height of the other will be


Two stones are thrown with the same speed but making different angles with the horizontal. Their ranges are equal. If the angle of projection of one is ?/3 and its maximum height is y1 then the maximum height of the other will be


Grade:10

2 Answers

Kenny Toijam
56 Points
10 years ago
If they have same horizontal ranges for different angles of projections,the angles are x/3 and (90°-x/3) The horizontal range for angle of projection x/3=u2 sin (2x/3) / g and range for 90°-(x/3)= u2 sin2[90°-(x/3)]/g=u2sin[180°-(2x/3)]/g But as the two ranges are equal as per the question,we get, x=(180*3)/4=135°.we know that y1=[u2*sin2(x/3)] / 2g for angle of projection (x/3) Let y2 be the maximum height for [90°-(x/3)] i.e y2= u2*sin2[ 90°-(x/3)] / 2g=y1*cot2(x/3)=y1*cot2(135/3)=y1.
keesom
22 Points
10 years ago
ADITI ........................ for equal ranges the angle of projections are theta & 90- theta and after finding the angle u can easily find the maximum height .

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