Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Two stones are projected with same speed but making different angles with horizontal such that their range are same if the angle of projection of one is pi/3 and find it's max.height of second

Two stones are projected with same speed but making different angles with horizontal such that their range are same if the angle of projection of one is pi/3 and find it's max.height of second 
 

Grade:11

1 Answers

Venkat
273 Points
3 years ago
Two stones are projected with same speed but making different angles with horizontal such that their range are same if the angle of projection of one is pi/3 and find it's max.height of second 
Ans : Maxium height of second is 1/3 rd of first one. Please find the solutrion below.
 
 
R_1=R_2 \\ \\\frac{u^2sin2\theta_1}{g}=\frac{u^2sin2\theta_2}{g} \\ \\sin2\theta_1=sin2\theta_2 \\sin\theta_1cos\theta_1=sin\theta_2cos\theta_2 \\\theta_1=60 \\sin60cos60=sin\theta_2cos\theta_2 \\\frac{\sqrt{3}}{2}\times {\frac{1}{2}}=2sin\theta_2 \\2sin\theta_2= \frac{\sqrt{3}}{4} \\\theta_2=60/2=30 \\ \\H_1=\frac{u^2sin^2\theta_1}{g}=\frac{u^2sin^260}{g}=\frac{3u^2}{8g}=y_1 \\ \\H_2=\frac{u^2sin^2\theta_2}{g}=\frac{u^2sin^230}{g}=\frac{u^2}{8g}=\frac{y_1}{3} \\H_1:H_2=1:\frac{1}{3}

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free