Two identical parallel plate capacitors are placed

Question

Two identical parallel plate capacitors are placed in series and connected to a constant voltage source of V volt. If one of the capacitors is completely immersed in a liquid with dielectric constant k, the potential difference between the plates of other capacitor will change to ?

deepak · Accepted Answer

if the capacitors are connected then before the introduction of the dielectric the voltage of each of them is V/2 by the formula for capacitance, Q=CV since the capacitors are connected in series therefore the charges on them must be a constant, therefore C is inversely propotional to V &hellip;.&hellip;.1 on introduction of a dielectric liq. of constant k, the capacitance of immersed capacitor becomes kC then the voltage(potentiall difference between the plates) on that capacitor wil become V/(1+k) &hellip;.&hellip;.by 1 then the voltage on the second capacitor will become V&minus;V/(1+k) hope this was useful

Electric Current> Two identical parallel plate capacitors a...

Two identical parallel plate capacitors are placed in series and connected to a constant voltage source of V volt. If one of the capacitors is completely immersed in a liquid with dielectric constant k, the potential difference between the plates of other capacitor will change to ?

yash lohar , 9 Years ago

deepak

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Electric Current> Two identical parallel plate capacitors a...

Two identical parallel plate capacitors are placed in series and connected to a constant voltage source of V volt. If one of the capacitors is completely immersed in a liquid with dielectric constant k, the potential difference between the plates of other capacitor will change to ?

yash lohar , 9 Years ago

deepak

LIVE ONLINE CLASSES

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