if the capacitors are connected then before the introduction of the dielectric the voltage of each of them is V/2
by the formula for capacitance,
Q=CV
since the capacitors are connected in series therefore the charges on them must be a constant,
therefore C is inversely propotional to V ….….1
on introduction of a dielectric liq. of constant k, the capacitance of immersed capacitor becomes kC
then the voltage(potentiall difference between the plates) on that capacitor wil become V/(1+k) ….….by 1
then the voltage on the second capacitor will become V−V/(1+k)
hope this was useful