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# Two conducting wires A and B (made of same material) of length 1 m and 2 m and area of cross sections 1 cm^2 and 100mm^2, respectively are taken. if the resistance of a wire  of length 5 m and thickness 2 cm made of same material as A and B is 5 ohms, then find the resistance of the new wire of length 5m formed by melting A and B.

Saurav
224 Points
2 years ago
just use the formula R=$\rho$ L/A
and conserve volume
5$\Omega$=$\rho$ *5*100/(pi* 1*1)          converted m into cm
$\rho$=pi/100
now total volume of a & b =V=100.02 * pi
area of new wire=V/ length of new wire
A=100.02*pi/500
R=$\rho$L/A
=(pi/100)(500)/((100.02*pi)/(500))
solve it and that’s the answer!