Two cells each of end 1.5 volt and internal resistance 5 ohm are joined in series with a resistance box and a resistance coil of 10 ohm. What resistance must be unplugged in the box in order that that p.d. across the ends of the ohm coil may be 0.1 volt?

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Shivansh · Answer

3V total emf, 10 ohm internal resistance, 0.1volt is dropped across the box, i e, 2.9V is across 10ohm. current = 2.9/10 = 0.29A hencer resistance = 0.1/0.29 = 0.345 ohm

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Two cells each of end 1.5 volt and internal resistance 5 ohm are joined in series with a resistance box and a resistance coil of 10 ohm. What resistance must be unplugged in the box in order that that p.d. across the ends of the ohm coil may be 0.1 volt?

Two cells each of end 1.5 volt and internal resistance 5 ohm are joined in series with a resistance box and a resistance coil of 10 ohm. What resistance must be unplugged in the box in order that that p.d. across the ends of the ohm coil may be 0.1 volt?

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Two cells each of end 1.5 volt and internal resistance 5 ohm are joined in series with a resistance box and a resistance coil of 10 ohm. What resistance must be unplugged in the box in order that that p.d. across the ends of the ohm coil may be 0.1 volt?

Two cells each of end 1.5 volt and internal resistance 5 ohm are joined in series with a resistance box and a resistance coil of 10 ohm. What resistance must be unplugged in the box in order that that p.d. across the ends of the ohm coil may be 0.1 volt?

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