Three equal resistors connected in series with a battery dissipate P Watts of power what will be the bear power dissipated if the same resistance are connected in parallel across the battery

Question

Arun · Answer

Let R be the value of each resistance. & V r be the voltage of battery. When the 3 resistance are connected in series, Power dissipated (P) = V 2 / 3R When they are connected in parallel, Power dissipated P' = 3 V 2 / R Hence P' = 9P

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Three equal resistors connected in series with a battery dissipate P Watts of power what will be the bear power dissipated if the same resistance are connected in parallel across the battery

Three equal resistors connected in series with a battery dissipate P Watts of power what will be the bear power dissipated if the same resistance are connected in parallel across the battery

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Three equal resistors connected in series with a battery dissipate P Watts of power what will be the bear power dissipated if the same resistance are connected in parallel across the battery

Three equal resistors connected in series with a battery dissipate P Watts of power what will be the bear power dissipated if the same resistance are connected in parallel across the battery

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