MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

The values of two resistors are R1 = (6 ±0.3)kΩ and R2 = (10±0.0.2)kΩ. The percentage error in the equivalent resistors when they are connected in parallel is : a) 5.125 %, b)2% , c) 3.125 %, d) 7%, e) 10.125%(answer) How do you get this answer? Thanks!

4 years ago

Answers : (1)

Mansi
13 Points
							R= R1*R2/R1+R2, where R is equivalent resistance %error in R = % error in R1*R2 +%error in R1+R2 %error in R1*R2 =%error in R1 + %error R2 %error in R1= 0.3/6*100= 5%% error in R2 = 0.2/10 * 100 = 2%% error in R1+ R2= 5%+2% =7%%error in R1 +R2 = 0.3+0.2/16 *100 = 3.125%Total error in R = 7%+3.125% =10.125%
						
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details