The time constant of LR circuit is 20 s.when a resistance of 2Ω is connected in series with R then time constant becomes 2s ,self inductance of circuit is ___
krishna priya , 8 Years ago
Grade 12
1 Answers
Vikas TU
Last Activity: 8 Years ago
t = 20 = L/R
and
after adding a resistance of 2 ohm,
t’ = L/(R + 2) = 2
dividing t/t’ we get,
(R+2)/R = 20/2 = 10
R = ¼ ohm and
L = 5 H
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