Sol. i = AST2 e^-∅/KT
i base 1 = i i base 2 = 100 mA
A base 1 = 60 * 10^4 A base 2 = 3 * 10^4
S base 1 = S S base 2 = S
T base 1 = 2000 T base 2 = 2000
∅ base 1 = 4.5 eV ∅ base 2 = 2.6 eV
K = 1.38 * 10^–23 J/k
i = (60 * 10^4) (S) * (2000)^2 e^-4.5*1.6*10^-19 /1.38*10^-23 *2000
100 = (3 * 10^4) (S) * (2000)^2 e^-2.6*1.6*10^-19 /1.38*10^-23 *2000
Dividing the equation
i/100 = e^[-4.5*1.6*10/1.38*2 (-2.6*1.6*10/1.38*20)]
⇒ i/100 = 20 * e^-11.014 ⇒ i/100 = 20 * 0.000016
⇒ i = 20 * 0.0016 = 0.0329 mA = 33 μA