Navjyot Kalra
Last Activity: 10 Years ago
Sol. r base p = (δV base p/ δl base p) at constant V base g
Consider the two points on V base g = -6 line
r base p = (240 - 160)V/(13 - 3) * 10^-3 A = 80/10 *10^3 Ω = 8KΩ
g base m = (δl base p/ δV base g)v base p = constant
considering the point on 200 V line,
g base m = (13 - 3) * 10^-3/[(-4) + (-8)] A = 10 * 10^-3/4 = 2.5 milli mho
μ = r base p * gm
= 8 * 10^3 Ω * 2.5 * 10^-3 Ω^-1 = 8 * 1.5 = 20