 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        The plate resistance and the amplification factor of a triode are 10 kΩ and 20. The tube is operated at plate voltage 250 V and grid voltage – 7.5 V. The plate current is 140 mA. (a) To what value should the grid voltage be )b) To what value should the plate voltage be changed to take the plate current back to 10 mA?`
5 years ago

```							Sol. r base p = 10 KΩ = 10 * 10^3 Ω
μ = 20 V base p = 250 V
V base g = –7.5 V I base p = 10 mA
a) g base m = (δl base p/δV base g)V base p = constant
⇒ δV base g = δl base p/g base m = 15 * 10^-3 – 10 * 10^-3/μ/r base p
= 5 * 10^-3/20/10 * 10^3 = 5/2 = 2.5
r’ base g = +2.5 – 7.5 = -5 V
b) r base p = (δV base p/δl base p)V base g = constant
⇒ 10^4 = δV base p/(15 * 10^-3 – 10 * 10^-3)
⇒ δV base p = 10^4 * 5 * 10^-3 = 50 V
V’ base p – V base p = 50 ⇒ V’ base p = -50 + V base p = 200 V

```
5 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Electric Current

View all Questions »  ### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions