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Grade 12th passElectric Current

the maximum current that can be measured by a galvanometer of resistance 40 ohm is 10mA. It is converted into a voltmeter that can read upto 50V. the resistance to be connected in series with the galvanometer is

Profile image of Achyuth Goud
8 Years agoGrade 12th pass
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3 Answers

Profile image of Arun
8 Years ago
To convert a galvanometer into voltmeter, the necessary value of resistance to be connected in series with the galvanometer is
R = V/ Ig  -  G
R = 5000 - 40
R = 4960 ohm
Profile image of Gitanjali Rout
8 Years ago
To convert a galvanometer into voltmeter, the necessary value of resistance to be connected in series with the galvanometer isR = V/ Ig  -  GR = 5000 - 40R = 4960 ohm
thanks
 
Profile image of Gitanjali Rout
8 Years ago
To convert a galvanometer into voltmeter, the necessary value of resistance to be connected in series with the galvanometer isR = V/ Ig  -  GR = 5000 - 40R = 4960 ohm.