The magnitude of J of the current density in a certain lab wire with a circular wire cross section of radius 2.00mm is given by (J=3*10^8)*r^2 with J in amperes per square metre. what is the current through outer section bounded by r=0.900R and r=R??

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Arun · Answer

Current = ∫ J dA = (2π)(3 x 10^8) ∫ r^3 dr from 1.8 x 10^-3 to 2 x 10^-3 = [(6π x 10^8)/4][16 - 1.8^4][10^-12] = 2.59 x 10^-3 amps.

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The magnitude of J of the current density in a certain lab wire with a circular wire cross section of radius 2.00mm is given by (J=310^8)r^2 with J in amperes per square metre. what is the current through outer section bounded by r=0.900R and r=R??

The magnitude of J of the current density in a certain lab wire with a circular wire cross section of radius 2.00mm is given by (J=310^8)r^2 with J in amperes per square metre. what is the current through outer section bounded by r=0.900R and r=R??

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The magnitude of J of the current density in a certain lab wire with a circular wire cross section of radius 2.00mm is given by (J=3*10^8)*r^2 with J in amperes per square metre. what is the current through outer section bounded by r=0.900R and r=R??

The magnitude of J of the current density in a certain lab wire with a circular wire cross section of radius 2.00mm is given by (J=3*10^8)*r^2 with J in amperes per square metre. what is the current through outer section bounded by r=0.900R and r=R??

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The magnitude of J of the current density in a certain lab wire with a circular wire cross section of radius 2.00mm is given by (J=310^8)r^2 with J in amperes per square metre. what is the current through outer section bounded by r=0.900R and r=R??

The magnitude of J of the current density in a certain lab wire with a circular wire cross section of radius 2.00mm is given by (J=310^8)r^2 with J in amperes per square metre. what is the current through outer section bounded by r=0.900R and r=R??