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The horizontal component of the earth’s magnetic field at a certain place is 3.010 -5 T andthe direction of the direction of the field is from the geographic south to the geographicnorth. A very long straight conductor is carrying a steady current of 1A. What is theforce per unit length on it when it is placed on a horizontal table and the direction of thecurrent is (a) east to west (b)south to north?
Let theta be the angle between magnetic feild and current flowing in the conductor1) F= I B sin theta = 1 *3*10^-5 * sin 90 = 3*10^-52) theta= 0Therefore, F=0.
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