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Grade: 12

                        

The horizontal component of the earth’s magnetic field at a certain place is 3.010 -5 T and the direction of the direction of the field is from the geographic south to the geographic north. A very long straight conductor is carrying a steady current of 1A. What is the force per unit length on it when it is placed on a horizontal table and the direction of the current is (a) east to west (b)south to north?

9 months ago

Answers : (1)

Shreya singh
13 Points
							
Let theta be the angle between magnetic feild and current flowing in the conductor
1) F= I B sin theta
      = 1 *3*10^-5 * sin 90
      = 3*10^-5
2) theta= 0
Therefore, F=0.
7 months ago
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