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Grade 12Electric Current

The current in a circuit with an external resistance of 3.75 ohm is 0.5 . when a resistance of 1ohm is introduce into the circuit the current becomes 0.4 .Then what will be the emf of the power source ? Please explain .

jogesh

8 Years agoGrade 12

1 Answer

Arun

Approved Tutor Answer8 Years ago

$E=2V$ $\implies E=0.4(3.75+1+r)=0.4(4.75+r)$ $E=i(R+R_1+r)$ is added to the circuit, $1\Omega$ When external resistance of $\implies E=0.5(3.75+r)$ , respectively.When external resistance of3.75 omega is connected, $r$ and $E$ et the EMF and internal resistance of the battery be

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