Shailendra Kumar Sharma
Last Activity: 7 Years ago
CURRENT THROUGH A SMALL AREA (dS) ON A SURFACE IS GIVENI BY = J.(dS)
IN ABOVE PRB = CURRENT(I) = J * PI( R^2 – (R/2)^2)
= 2.0*105*3.14(4-1)*10^-3
IN THE SECOND CASE CURRENT CAN BE FOUND BY USINIG A SMALL CIRCULAR ELEMENT OF RADIUS (dr) = Area of small circular portion is(dS) = (2*pi*r)*dr
current through this portion is = J.dS = ( a*r^2)*(2*pi*r)*dr
after integrating J.dS from R/2 TO R WE CAN FIND CURRENT THROUGH OUTER PORTION.