×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
the coordinates of foot of perpendicular (7,14,5) to the plane 2x+4y-z=2 is

```
8 months ago

## Answers : (1)

2069 Points
```							I assume you wish to know the foot of perpendicular FROM P(7, 14, 5) to the plane 2x+4y-z= 2.Let the foot of perpendicular be (a, b, c). Clearly, the vector (a-7)i + (b-14)j + (c-15)k is parallel to the normal of the plane, viz. 2i+4j-k.Hence (a-7)i + (b-14)j + (c-5) k = m(2i+4j-k) where m is a constant.Comparing, we have a-7= 2m...(1)b-14= 4m ....(2)And c-5= -m....(3)Also, (a,b,c) lies on the plane, and thus satisfies the eq. 2a+4b-c=2....(4)Hence we have 4 eqns and 4 variables a, b, c, m. Solving these we get the required values of a, b, c and hence the point P's coordinates asP(1, 2, 8).KINDLY APPROVE :))
```
8 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Electric Current

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

Have any Question? Ask Experts

Post Question