Temperature of a wire is increased by 3°C, when a current is passed in the wire for sometime. If the current is doubled , then by what amount will the temperature of wire increase during same interval of time.

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Arun · Answer

Dear Sneha As we know H = I&sup2; Rt Hence H 1 /H 2 = (I 1 )&sup2;/(I 2 )&sup2; H 2 /H 1 = 4 Now Theta proportional to H Now &theta; 2 /&theta; 1 = H 2 /H 1 &theta; 2 = 4 * 3 = 12 &deg;c Regards Arun (askIITians forum expert)

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Temperature of a wire is increased by 3°C, when a current is passed in the wire for sometime. If the current is doubled , then by what amount will the temperature of wire increase during same interval of time.

Temperature of a wire is increased by 3°C, when a current is passed in the wire for sometime. If the current is doubled , then by what amount will the temperature of wire increase during same interval of time.

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Temperature of a wire is increased by 3°C, when a current is passed in the wire for sometime. If the current is doubled , then by what amount will the temperature of wire increase during same interval of time.

Temperature of a wire is increased by 3°C, when a current is passed in the wire for sometime. If the current is doubled , then by what amount will the temperature of wire increase during same interval of time.

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