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suppose a pendulum of mass m moving in horizontal circle with string length =r and the centripetal petal force=-k/r^2 .now what is the total energy of pendulum now acc to me mv^2/r=-k/r^2 so mv^2=-k/rso KE=1/2mv^2 putting the value of mv^2 we get KE=-k/2r and this is the given ans.but where is PE.that is equal to -mgr if we take point of hanging as reference point


suppose a pendulum of mass m moving in horizontal circle with string length =r and the centripetal petal force=-k/r^2 .now what is the total energy of pendulum now acc to me      mv^2/r=-k/r^2 so   mv^2=-k/rso KE=1/2mv^2     putting the value of mv^2 we get KE=-k/2r     and this is the given ans.but where is PE.that is equal to -mgr if we take point of hanging as reference point


Grade:11

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