Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
suppose a pendulum of mass m moving in horizontal circle with string length =r and the centripetal petal force=-k/r^2 .now what is the total energy of pendulum now acc to me mv^2/r=-k/r^2 so mv^2=-k/rso KE=1/2mv^2 putting the value of mv^2 we get KE=-k/2r and this is the given ans.but where is PE.that is equal to -mgr if we take point of hanging as reference point
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !