Sir..... x = 2 + [x÷(x+1)] How he wrote. What are series and what are parallel in the circuit. Explain sir.

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Vikas TU · Answer

Dear student First short the wire , The series resistance will be 2 ohm , and remaining x and 1 ohm is in parallel. Hope this help Good Luck

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Sir..... x = 2 + [x÷(x+1)] How he wrote. What are series and what are parallel in the circuit. Explain sir.

Sir.....
x = 2 + [x÷(x+1)]
How he wrote.
What are series and what are parallel in the circuit.
Explain sir.

1 Answers

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Sir..... x = 2 + [x÷(x+1)] How he wrote. What are series and what are parallel in the circuit. Explain sir.

Sir.....x = 2 + [x÷(x+1)]How he wrote.What are series and what are parallel in the circuit.Explain sir.

1 Answers

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Sir.....
x = 2 + [x÷(x+1)]
How he wrote.
What are series and what are parallel in the circuit.
Explain sir.