Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Sir in point 10
It is given imax= E/R and Pmax=E2/4R.
But sir P=I2R therefore, it should be----
Pmax=(E/R)2*R=E2/R.
one month ago

Piyush Kumar Behera
419 Points

Actually there is little confusion about the point written as the point has been over shortened.

Here is the actuall concept.
The  I max term is used to depict the maximum cureent through the wire and taking internal resistance zero. You get the required result.

But there is something known as maximum power transfer theorem in this concept.
For it you must understand that internal resistance of a cell cannot be altered by a person setting up the apparatus.It would remain the same as it would be constructed.
The maximum power transfer theorem states that maximum power is transfered to the external resistance in a circuit when the external resistance is equal to the internal resistance.So in that case r= R.
and $I=\frac{E}{R+r}$
$\Rightarrow I=\frac{E}{2R}$
So hence we can calculate the maximum power.
Here in the book it is given in that sense.
I hope it helps!!

Piyush Kumar Behera
one month ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Electric Current

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions