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Question is attached in the picture.. [DOP-PCE pg-506 Q21]

Question is attached in the picture..
[DOP-PCE pg-506 Q21]

Question Image
Grade:12th pass

1 Answers

Abhishek Kumar
askIITians Faculty 253 Points
6 years ago
Let the resistance is proportional to the length and total resistance R.
So, Rl1 = R0l1/L where L = circumference of wire = (l1 + l2)
So, Rl2 = R0l2/L
Req = Rl1xRl2/(Rl1 + Rl2) = 8/3
Put the value and find the answer.

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