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Point charges q1=2 and q2=-1 are at oint x=0 and x=6 respectively.Electrial potential will be zero at points
Electric potential will be zero on the straight line in between the two point charges in case of th charges being of opposite sign. Equation: 2k/r – 1k/(6-r) = 0 gives r = 4, which means the electric potential is zero at a distance of 4 from q1, i.e., at x = 4
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