Point charges q1=2 and q2=-1 are at oint x=0 and x=6 respectively.Electrial potential will be zero at points

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Karan Gupta · Answer

Electric potential will be zero on the straight line in between the two point charges in case of th charges being of opposite sign. Equation: 2k/r &ndash; 1k/(6-r) = 0 gives r = 4, which means the electric potential is zero at a distance of 4 from q1, i.e., at x = 4

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Point charges q1=2 and q2=-1 are at oint x=0 and x=6 respectively.Electrial potential will be zero at points

Point charges q1=2 and q2=-1 are at oint x=0 and x=6 respectively.Electrial potential will be zero at points

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