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We have, Initial charges are 10 × 10-6 C and 20 × 10-6 C. Suppose they are separated by distance ‘r’. Now,
(9 × 109)×(10 × 10-6)×(20 × 10-6)/r2 = F
Now, the new charges are [(10+8) × 10-6 C] and [(20+8) × 10-6 C] or (18 × 10-6 C) and (28 × 10-6 C). The new force between the two is,
F’ = (9 × 109)×(18 × 10-6)×(28 × 10-6)/r2
Now you can find ratio.
Regards
Arun
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