Plz send derivation of this relation of equivalent power in series
Adam , 7 Years ago
Grade 12
Electric Current> Plz send derivation of this relation of e...
1 Answers
Arun
Last Activity: 7 Years ago
Let I be the current through the series circuit.
Let R1,R2 and R3 be the three resistors.
P1,P2 and P3 be the power consumed across R1,R2 and R3 respectively.
So,P1=I^2R1
P2=I^2R2
P3=I^2R3
Since power is a scalar quantity,the net power consumed in the series circuit
P=P1+P2+P3=I^2R1+I^2R2+I^2R3
P=I^2(R1+R2+R3)=I^2 X total resistance R
The reciprocal of power 1/P=1/VI,V is the total p.d. across the series circuit.
1/P=R/I^2=(R1+R2+R3)/I^2=R1/I^2 + R2/I^2+ R3/I^2=1/P1 +1/P2+1/P3(proved)
Let R1,R2 and R3 be the three resistors.
P1,P2 and P3 be the power consumed across R1,R2 and R3 respectively.
So,P1=I^2R1
P2=I^2R2
P3=I^2R3
Since power is a scalar quantity,the net power consumed in the series circuit
P=P1+P2+P3=I^2R1+I^2R2+I^2R3
P=I^2(R1+R2+R3)=I^2 X total resistance R
The reciprocal of power 1/P=1/VI,V is the total p.d. across the series circuit.
1/P=R/I^2=(R1+R2+R3)/I^2=R1/I^2 + R2/I^2+ R3/I^2=1/P1 +1/P2+1/P3(proved)
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