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Please solve Q.2. ๐Ÿฅฐ๐Ÿฅฐ๐Ÿฅฐ๐Ÿฅฐ๐Ÿ˜๐Ÿฅฐ๐Ÿ˜›๐Ÿ˜‹๐Ÿ˜ฃ๐Ÿคซ๐Ÿ™๐Ÿคซ๐Ÿ™„๐Ÿค๐Ÿ™„๐Ÿค๐Ÿคซ๐Ÿง๐Ÿคซ๐Ÿง๐Ÿคซ๐Ÿง๐Ÿคซ๐Ÿง๐Ÿคซ๐Ÿง๐Ÿค๐Ÿง๐Ÿค๐Ÿ˜•๐Ÿค๐Ÿง๐Ÿคซ๐Ÿคซ๐Ÿ™„๐Ÿคซ๐Ÿ™„๐Ÿคซ๐Ÿ™„๐Ÿคซ๐Ÿ™„๐Ÿ˜ฒ๐Ÿคซ๐Ÿคซ๐Ÿ™„๐Ÿคซ๐Ÿ˜Ÿ๐Ÿค๐Ÿ˜Ÿ๐Ÿค๐Ÿ˜•๐Ÿค๐Ÿ˜Ÿ๐Ÿค๐Ÿ˜•๐Ÿค๐Ÿค๐Ÿ˜•๐Ÿค๐Ÿง๐Ÿค

Please solve Q.2.
๐Ÿฅฐ๐Ÿฅฐ๐Ÿฅฐ๐Ÿฅฐ๐Ÿ˜๐Ÿฅฐ๐Ÿ˜›๐Ÿ˜‹๐Ÿ˜ฃ๐Ÿคซ๐Ÿ™๐Ÿคซ๐Ÿ™„๐Ÿค๐Ÿ™„๐Ÿค๐Ÿคซ๐Ÿง๐Ÿคซ๐Ÿง๐Ÿคซ๐Ÿง๐Ÿคซ๐Ÿง๐Ÿคซ๐Ÿง๐Ÿค๐Ÿง๐Ÿค๐Ÿ˜•๐Ÿค๐Ÿง๐Ÿคซ๐Ÿคซ๐Ÿ™„๐Ÿคซ๐Ÿ™„๐Ÿคซ๐Ÿ™„๐Ÿคซ๐Ÿ™„๐Ÿ˜ฒ๐Ÿคซ๐Ÿคซ๐Ÿ™„๐Ÿคซ๐Ÿ˜Ÿ๐Ÿค๐Ÿ˜Ÿ๐Ÿค๐Ÿ˜•๐Ÿค๐Ÿ˜Ÿ๐Ÿค๐Ÿ˜•๐Ÿค๐Ÿค๐Ÿ˜•๐Ÿค๐Ÿง๐Ÿค
ย  ย  ย  ย  ย ย 

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Grade:7

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
576-1431_IMG_20191217_173213.jpg
Vikas TU
14149 Points
4 years ago
Dear studentย 
Simply understand this byย  : In series voltage drop ccursย  so P = V^2/Rย  so power wil be reduced.
In parallel voltage wil be same so power will depend on resistance of material .
Hope this clears.
Good Luckย 

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