Its very easy. Its just about the combination of capacitors. Basically, you gotta remember that when two capacitors C1 and C2 are connected in parallel and series, then
Cp = C1+C2 and Cs = C1C2/(C1+C2)
Now, the box capacitance of 6uF and 12uF is 4uF since both of them are connected in series.
The equivalent capacitance of the combination when 3uF is replaced with xuF is 8uF i.e.,
8 = 9.(x+11+4) / 9+(x+11+4)
On simplifying the above, we get x=57uF.
Hope that’ll help.