Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

please see the image.

please see the image.

Question Image
Grade:12

1 Answers

Yash Jain
55 Points
6 years ago
Its very easy. Its just about the combination of capacitors. Basically, you gotta remember that when two capacitors C1 and C2 are connected in parallel and series, then 
Cp = C1+C2 and Cs = C1C2/(C1+C2)
Now, the box capacitance of 6uF and 12uF is 4uF since both of them are connected in series.
The equivalent capacitance of the combination when 3uF is replaced with xuF is 8uF i.e.,
8 = 9.(x+11+4) / 9+(x+11+4)
On simplifying the above, we get x=57uF.
Hope that’ll help.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free