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Please give the answer to this question. In arihant book the answer is given as 1350

MANAV S , 6 Years ago
Grade 12
anser 1 Answers
Vikas TU
Omega = 1000 rad/sec.
Xl = Omega* L 
Xl = 1000* 0.1 = 100 ohm 
Similarly Xc = 1/(omega*C)
Xc = 500 ohm.
Qheta = tan-1(Xl- Xc)/ R
So, theta comes to be tan-1(-1)
which is equal to 135 degree (2nd quadrant)
 
Last Activity: 6 Years ago
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