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Grade 12th passElectric Current

Obtain the equivalent resistance seen from the input or source terminals and the source current for the circuit shown in figure

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Profile image of Soham Patel
4 Years agoGrade 12th pass
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1 Answer

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ApprovedApproved Tutor Answer11 Months ago

To determine the equivalent resistance seen from the input or source terminals and the source current in a given circuit, we need to analyze the configuration of the resistors and their connections. Although I can't see the figure you mentioned, I can guide you through the general process of finding the equivalent resistance and source current in a circuit with resistors in series and parallel.

Finding Equivalent Resistance

The equivalent resistance (R_eq) can be calculated based on how the resistors are arranged. Here are the steps for both series and parallel configurations:

Resistors in Series

  • When resistors are connected in series, the total or equivalent resistance is simply the sum of the individual resistances.
  • Mathematically, this is expressed as: R_eq = R1 + R2 + R3 + ... + Rn

For example, if you have three resistors in series with values of 2Ω, 3Ω, and 5Ω, the equivalent resistance would be:

R_eq = 2Ω + 3Ω + 5Ω = 10Ω

Resistors in Parallel

  • For resistors connected in parallel, the reciprocal of the equivalent resistance is the sum of the reciprocals of the individual resistances.
  • This can be expressed as: 1/R_eq = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn

For instance, if you have two resistors in parallel with values of 4Ω and 6Ω, the equivalent resistance would be calculated as follows:

1/R_eq = 1/4Ω + 1/6Ω

1/R_eq = 3/12 + 2/12 = 5/12

R_eq = 12/5 = 2.4Ω

Calculating Source Current

Once you have the equivalent resistance, you can find the source current (I) using Ohm's Law, which states:

I = V/R

Here, V is the voltage of the source, and R is the equivalent resistance you just calculated. For example, if the voltage source is 12V and the equivalent resistance is 2.4Ω, the source current would be:

I = 12V / 2.4Ω = 5A

Example Scenario

Let’s say you have a circuit with a 12V battery connected to three resistors: 2Ω in series with a parallel combination of 4Ω and 6Ω. First, calculate the equivalent resistance of the parallel resistors:

1/R_parallel = 1/4Ω + 1/6Ω = 5/12

R_parallel = 12/5 = 2.4Ω

Now, add the series resistor:

R_eq = 2Ω + 2.4Ω = 4.4Ω

Finally, apply Ohm's Law to find the source current:

I = 12V / 4.4Ω ≈ 2.73A

This methodical approach allows you to analyze various circuits effectively. If you have a specific circuit diagram, feel free to describe it, and I can provide a more tailored explanation!