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In Wheatstone's bridge P=9ohm , Q=11ohm , R=4ohm and S=6ohm . How much resistance must be put in parallel to the resistance S to balance the bridge

In Wheatstone's bridge P=9ohmQ=11ohmR=4ohm and S=6ohm. How much resistance must be put in parallel to the resistance S to balance the bridge
 

Grade:12

1 Answers

Arun
25763 Points
2 years ago
Dear student
 
9/11 = 4 /(6R/6+R)
 
10 R = 264
 
hence R = 26.4 ohm
 
hopeit helps
 
Reagards (askIITians forum expert)

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