In Wheatstone's bridge P=9ohm , Q=11ohm , R=4ohm and S=6ohm . How much resistance must be put in parallel to the resistance S to balance the bridge

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Arun · Answer

Dear student 9/11 = 4 /(6R/6+R) 10 R = 264 hence R = 26.4 ohm hopeit helps Reagards (askIITians forum expert)

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In Wheatstone's bridge P=9ohm , Q=11ohm , R=4ohm and S=6ohm . How much resistance must be put in parallel to the resistance S to balance the bridge

In Wheatstone's bridge P=9ohm, Q=11ohm, R=4ohm and S=6ohm. How much resistance must be put in parallel to the resistance S to balance the bridge

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In Wheatstone's bridge P=9ohm , Q=11ohm , R=4ohm and S=6ohm . How much resistance must be put in parallel to the resistance S to balance the bridge

In Wheatstone's bridge P=9ohm, Q=11ohm, R=4ohm and S=6ohm. How much resistance must be put in parallel to the resistance S to balance the bridge

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