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In the given figure the potential difference across 3 microfarad capacitor will be: 16V 10V 6V 4V

In the given figure the potential difference across 3 microfarad capacitor will be:
  1. 16V
  2. 10V
  3. 6V
  4. 4V

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1 Answers

Vikas TU
14149 Points
2 years ago
The capacitors are in series and emf as wel as, therefore the net capacitance becomes= > 
Ct = C1C2/(C1 + C2) => 15/8 uF.
Net emf = 20 – 4 = 16 V.
 
Voltage across 3 uF => (Ct/C1)*V => (15/(8*3))*16 = > 10 volts.

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