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Grade 12th passElectric Current

In L–C–R series AC circuit voltage amplitude across L, C and R are 10V, 6Vand 3V respectively. At an instant voltage across the resistance is 3√3 /2 volt and source voltage is decreasing then what can we say about the current in the circuit at that instant.(increasing or decreasing) explain

Profile image of suraj
10 Years agoGrade 12th pass
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1 Answer

Profile image of Vikas TU
10 Years ago
Current in the L-C-R circuit,
i = Vsource/Znet = > (10 + 6 + 3)/root((wl)^2 + (1/wc)^2 + R^2) = > 19/root((wl)^2 + (1/wc)^2 + R^2)
i’ = Vsource/Znet => (10 + 6 + 3root3/2)/Znet = >(16 + 3root3/2)/root((wl)^2 + (1/wc)^2 + R^2)
=> 18.59/root((wl)^2 + (1/wc)^2 + R^2)
Thus source voltage decreases and net impedence reamins same.
the current in circuit will too decrease.
as it is directly proprotional to vilatage source.