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# In L–C–R series AC circuit voltage amplitude across L, C and R are 10V, 6Vand 3V respectively. At an instant voltage across the resistance is 3√3 /2 volt and source voltage is decreasing then what can we say about the current in the circuit at that instant.(increasing or decreasing) explain

Vikas TU
14149 Points
5 years ago
Current in the L-C-R circuit,
i = Vsource/Znet = > (10 + 6 + 3)/root((wl)^2 + (1/wc)^2 + R^2) = > 19/root((wl)^2 + (1/wc)^2 + R^2)
i’ = Vsource/Znet => (10 + 6 + 3root3/2)/Znet = >(16 + 3root3/2)/root((wl)^2 + (1/wc)^2 + R^2)
=> 18.59/root((wl)^2 + (1/wc)^2 + R^2)
Thus source voltage decreases and net impedence reamins same.
the current in circuit will too decrease.
as it is directly proprotional to vilatage source.