Kulchandra
Last Activity: 8 Years ago
Force applied by q on q is f=kq^2/ASame will be the force on q by q now force on -q by q f=-Kq^2/A There will be 2 forces apllying on -q at angle 60° from each other therefore resultant force on -q will be (f)^1/3 direction will be towards triangle i.e f=(-kq^2/A)^1/3 .Now there will be two equal forces acting on q with angle 120° with each other the resultant wil be f only i.e resultant f will be f=k q^2/A