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In a straight conductor of uniform crosss section charge q is flowing for time t. Let s be the specific charge of an electron. the momentum of all the free electrons per unit length of the conductor . due to their drift velocity only is
Answer is q/ts

raghavendra , 8 Years ago
Grade 10
anser 1 Answers
venketep prasad m c

Last Activity: 8 Years ago

@raghavendra  I = nAeVd  where n = no. of electrons per unit volume, A= area of cross section of the wire , e = charge of an electron , V= drift velocity
what we want is momentum per unit length of wire.(ie) mV, where m is the total mass of all electrons in the unit length of wire. here  I = (q/t) = nAeV. and m = n*(A*1)*(me). As n = no. of electrons per unit volume and A*1 is the volume of the unit length cross section and me is the mass of one electron.
Therefore mV = (nAVd)*m= (q*me)/(t*e)
As e/me = specific charge  = s,
mVd  = q/(t*s)

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