Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

In a series LCR circuit with an AC source, R = 300 Ω, C = 20 μF, L = 1.0 henry, ℰ^0 = 50 V and v = 50/π Hz. Find (a) the rms current in the circuit and (b) the rms potential difference across the capacitor, the resistor and the inductor. Note that the sum of the rms potential difference across the three elements is greater than the rms voltage of the source.

In a series LCR circuit with an AC source, R = 300 Ω, C = 20 μF, L = 1.0 henry, ℰ^0 = 50 V and v = 50/π Hz. Find (a) the rms current in the circuit and (b) the rms potential difference across the capacitor, the resistor and the inductor. Note that the sum of the rms potential difference across the three elements is greater than the rms voltage of the source.

Grade:upto college level

1 Answers

Aditi Chauhan
askIITians Faculty 396 Points
7 years ago
Sol. R = 300Ω, C = 20 μF = 20 * 10^-6 F L = 1Henry, E = 50 V V = 50/π Hz (a) I base 0 = E base 0/Z , Z = √R^2 + (X base c – X base L)^2 = √(300)^2 + (1/2πfC - 2πfL)^2 = √(300)^2 + (1/2π* 50/π *20 * 10^-6 - 2π * 50/π * 1)^2 = √(300)^2 +(10^4/20 - 100)^2 = 500 I base 0 E base 0/Z = 50/500 = 0.1 A (b) Potential across the capacitor = I base 0 × X base c = 0.1 × 500 = 50 V Potential difference across the resistor = I base 0 × R = 0.1 × 300 = 30 V Potential difference across the inductor = I base 0 × X base L = 0.1 × 100 = 10 V Rms. potential = 50 V Net sum of all potential drops = 50 V + 30 V + 10 V = 90 V Sum or potential drops > R.M.S potential applied.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free