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If the current in 8 Ω resistance is 2A then the current through resistance 'R' would be :

AKSHAY CHAUHAN , 10 Years ago
Grade 12
anser 1 Answers
Sumit Majumdar

Last Activity: 10 Years ago

Dear student,
The potential difference across the ends of 8 ohm restsiatnce is equal to 16 V.
Hence, the current flowing through the resistance R would be equal to:
I=\left (8\times 2 \right )\frac{8+4}{8\times4}=6 amp
Regards

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