Electric Current> If a copper wire is stretched to make it ...

If a copper wire is stretched to make it 0.1%longer. The percentage change in its resistance is

Spurthy , 7 Years ago

Grade 10

3 Answers

Athul Joseph

Volume is constant during stretching.A*l=constantpi*r^2*l=constantl inversely proportional to r^2Using errors(Дl/l)*1000.-2*(Дr/r)*100Change in radius is equal to 0.2%Using errors again% change in resistance=4*(Дr/l)*100=4*0.2=0.8%

Last Activity: 7 Years ago

Khimraj

As resistance is directly proportional to the square of the length keeping its volume constant then by diffrentiating partially on both side we gey dR/R= 2*dL/L. But given dL/L=0.1 so persentage change in the resistance dR/R=2*0.1=0.2%

Last Activity: 7 Years ago

Athul Joseph

For small change in length bu stretching(less than 8%)u can use the equationdR/R=4*dl/L.so the answer is 4*0.1=0.4.if u need derivation just ask.my previous solution is wrong.sorry.😀

Last Activity: 7 Years ago