0

Guest

Courses New

I modified the circuit as much as I can. Can I modify it any further?

I modified the circuit as much as I can. Can I modify it any further?

Question Image
Grade:12

1 Answers

Sujit Kumar
111 Points
6 years ago
That modification is incorrect...
Starting from the right
2\Omega + 1\Omega=3\Omega (Series Resistance)
{(\frac{1}{6}\Omega+\frac{1}{3}\Omega)}^{-1}=2\Omega (Parallel Resistance) 
2\Omega+2\Omega=4\Omega(Series Resistance)
{(\frac{1}{4}\Omega+\frac{1}{3}\Omega)}^{-1}=\frac{12}{7}\Omega(Parallel Resistance)
\frac{12}{7}\Omega+4\Omega+4\Omega=\frac{68}{7}\Omega=9\frac{5}{7}\Omega \approx 9.7\Omega(Series Resistance)
Finaly the Circuit will be left with only one resistor of 9.7\Omega and a cell of 120V

Think You Can Provide A Better Answer ?

Other Related Questions on Electric Current

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More