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I am having problem finding current in individual sections. Can someone help me out fast please.

I am having problem finding current in individual sections. Can someone help me out fast please.

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Grade:12

2 Answers

Sandeep Bhamoo
443 Points
5 years ago
For last two parts with 2 and 2+1 voltage is same hence2×1=i•3, i=2/3. Now in 2 ohm just before them current = 1+2/3= 5/3. For 6 and 2+2 or2+2+1 voltage is same 6i= 2(5/3) +2(1) ,i=8/9. Now for staring 2 ohm resistor i=5/3+8/9 = 2 hence net potential of battrry = 2×2+6×(8/9) =28/3 please do approve my answer if correct
Kiran Gill
14 Points
5 years ago
The method is correct but as you can see the answer isn`t matching any of the option. Can someone please help me get any of the answer.

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